1/(3+x^2)^0.5

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Solution for 1/(3+x^2)^0.5 equation: 


D( x )

(x^2+3)^0.5 = 0

x^2+3 < 0

(x^2+3)^0.5 = 0

(x^2+3)^0.5 = 0

1*x^2 = -3 // : 1

x^2 = -3

x^2+3 < 0

x^2+3 < 0

1*x^2 < -3

1*x^2 < -3 // : 1

x^2 < -3/1

x^2 < -3

x belongs to the empty set

x in (-oo:+oo)

1/((x^2+3)^0.5) = 0

x belongs to the empty set

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